捕获asyncio.ensure_future中的错误

Question

我有以下代码：

try:
    asyncio.ensure_future(data_streamer.sendByLatest())
except ValueError as e:
    logging.debug(repr(e))

data_streamer.sendByLatest()可以提出ValueError，但是没有被抓住。

Answer 1

ensure_future-只需创建Task并立即返回。您应该等待创建的任务来获得结果（包括引发异常的情况）：

import asyncio


async def test():
    await asyncio.sleep(0)
    raise ValueError('123')


async def main():    
    try:
        task = asyncio.ensure_future(test())  # Task aren't finished here yet 
        await task  # Here we await for task finished and here exception would be raised 
    except ValueError as e:
        print(repr(e))


if __name__ == '__main__':
    loop = asyncio.get_event_loop()
    loop.run_until_complete(main())

输出：

ValueError('123',)

如果您不打算在创建任务后立即等待，可以稍后再等待（以了解任务如何完成）：

async def main():    
    task = asyncio.ensure_future(test())
    await asyncio.sleep(1)
    # At this moment task finished with exception,
    # but we didn't retrieved it's exception.
    # We can do it just awaiting task:
    try:
        await task  
    except ValueError as e:
        print(repr(e))

输出是相同的：

ValueError('123',)